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(x+2)(x-1)=22
We move all terms to the left:
(x+2)(x-1)-(22)=0
We multiply parentheses ..
(+x^2-1x+2x-2)-22=0
We get rid of parentheses
x^2-1x+2x-2-22=0
We add all the numbers together, and all the variables
x^2+x-24=0
a = 1; b = 1; c = -24;
Δ = b2-4ac
Δ = 12-4·1·(-24)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{97}}{2*1}=\frac{-1-\sqrt{97}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{97}}{2*1}=\frac{-1+\sqrt{97}}{2} $
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