(4x-15)=(x+1)+(x-1)

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Solution for (4x-15)=(x+1)+(x-1) equation: 



(4x-15)=(x+1)+(x-1)

We move all terms to the left:

(4x-15)-((x+1)+(x-1))=0

We get rid of parentheses

4x-((x+1)+(x-1))-15=0



We calculate terms in parentheses: -((x+1)+(x-1)), so:

(x+1)+(x-1)

We get rid of parentheses

x+x+1-1

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

2x-15=0

We move all terms containing x to the left, all other terms to the right

2x=15

x=15/2

x=7+1/2

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