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-6s^2+5s-1=0
a = -6; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·(-6)·(-1)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-1}{2*-6}=\frac{-6}{-12} =1/2 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+1}{2*-6}=\frac{-4}{-12} =1/3 $
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