12n-(4n-6)=3n-(9n-27)

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Solution for 12n-(4n-6)=3n-(9n-27) equation: 



12n-(4n-6)=3n-(9n-27)

We move all terms to the left:

12n-(4n-6)-(3n-(9n-27))=0

We get rid of parentheses

12n-4n-(3n-(9n-27))+6=0



We calculate terms in parentheses: -(3n-(9n-27)), so:

3n-(9n-27)

We get rid of parentheses

3n-9n+27

We add all the numbers together, and all the variables

-6n+27

Back to the equation:

-(-6n+27)



We add all the numbers together, and all the variables

8n-(-6n+27)+6=0

We get rid of parentheses

8n+6n-27+6=0

We add all the numbers together, and all the variables

14n-21=0

We move all terms containing n to the left, all other terms to the right

14n=21

n=21/14

n=1+1/2

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