2t(2-t)=1+t(1-2t)

Solution for 2t(2-t)=1+t(1-2t) equation:

2t(2-t)=1+t(1-2t)

We move all terms to the left:

2t(2-t)-(1+t(1-2t))=0

We add all the numbers together, and all the variables

2t(-1t+2)-(1+t(-2t+1))=0

We multiply parentheses

-2t^2+4t-(1+t(-2t+1))=0


We calculate terms in parentheses: -(1+t(-2t+1)), so:

1+t(-2t+1)

determiningTheFunctionDomain
t(-2t+1)+1

We multiply parentheses

-2t^2+t+1

Back to the equation:

-(-2t^2+t+1)


We get rid of parentheses

-2t^2+2t^2-t+4t-1=0

We add all the numbers together, and all the variables

3t-1=0

We move all terms containing t to the left, all other terms to the right

3t=1

t=1/3

t=1/3