-6b+3(b-5)=6(2-5b)

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Solution for -6b+3(b-5)=6(2-5b) equation: 



-6b+3(b-5)=6(2-5b)

We move all terms to the left:

-6b+3(b-5)-(6(2-5b))=0

We add all the numbers together, and all the variables

-6b+3(b-5)-(6(-5b+2))=0

We multiply parentheses

-6b+3b-(6(-5b+2))-15=0



We calculate terms in parentheses: -(6(-5b+2)), so:

6(-5b+2)

We multiply parentheses

-30b+12

Back to the equation:

-(-30b+12)



We add all the numbers together, and all the variables

-3b-(-30b+12)-15=0

We get rid of parentheses

-3b+30b-12-15=0

We add all the numbers together, and all the variables

27b-27=0

We move all terms containing b to the left, all other terms to the right

27b=27

b=27/27

b=1

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