2x/9=(3x-4)/2

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Solution for 2x/9=(3x-4)/2 equation:



2x/9=(3x-4)/2
We move all terms to the left:
2x/9-((3x-4)/2)=0
We calculate fractions
4x^2/()+(-((3x-4)*9)/()=0
We calculate terms in parentheses: +(-((3x-4)*9)/(), so:
-((3x-4)*9)/(
We multiply all the terms by the denominator
-((3x-4)*9)
We calculate terms in parentheses: -((3x-4)*9), so:
(3x-4)*9
We multiply parentheses
27x-36
Back to the equation:
-(27x-36)
We get rid of parentheses
-27x+36
Back to the equation:
+(-27x+36)
We get rid of parentheses
4x^2/()-27x+36=0
We multiply all the terms by the denominator
4x^2-27x*()+36*()=0
We add all the numbers together, and all the variables
4x^2-27x*()=0

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