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3x-3(7x+3)=3(1-7x)+4x
We move all terms to the left:
3x-3(7x+3)-(3(1-7x)+4x)=0
We add all the numbers together, and all the variables
3x-3(7x+3)-(3(-7x+1)+4x)=0
We multiply parentheses
3x-21x-(3(-7x+1)+4x)-9=0
We calculate terms in parentheses: -(3(-7x+1)+4x), so:We add all the numbers together, and all the variables
3(-7x+1)+4x
We add all the numbers together, and all the variables
4x+3(-7x+1)
We multiply parentheses
4x-21x+3
We add all the numbers together, and all the variables
-17x+3
Back to the equation:
-(-17x+3)
-18x-(-17x+3)-9=0
We get rid of parentheses
-18x+17x-3-9=0
We add all the numbers together, and all the variables
-1x-12=0
We move all terms containing x to the left, all other terms to the right
-x=12
x=12/-1
x=-12
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