-6a+3=10-(2a-1)

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Solution for -6a+3=10-(2a-1) equation: 



-6a+3=10-(2a-1)

We move all terms to the left:

-6a+3-(10-(2a-1))=0



We calculate terms in parentheses: -(10-(2a-1)), so:

10-(2a-1)

determiningTheFunctionDomain
-(2a-1)+10

We get rid of parentheses

-2a+1+10

We add all the numbers together, and all the variables

-2a+11

Back to the equation:

-(-2a+11)



We get rid of parentheses

-6a+2a-11+3=0

We add all the numbers together, and all the variables

-4a-8=0

We move all terms containing a to the left, all other terms to the right

-4a=8

a=8/-4

a=-2

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