-6=3(j-15)+-12

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Solution for -6=3(j-15)+-12 equation: 



-6=3(j-15)+-12

We move all terms to the left:

-6-(3(j-15)+-12)=0

We use the square of the difference formula

-(3(j-15)-12)-6=0



We calculate terms in parentheses: -(3(j-15)-12), so:

3(j-15)-12

We multiply parentheses

3j-45-12

We add all the numbers together, and all the variables

3j-57

Back to the equation:

-(3j-57)



We get rid of parentheses

-3j+57-6=0

We add all the numbers together, and all the variables

-3j+51=0

We move all terms containing j to the left, all other terms to the right

-3j=-51

j=-51/-3

j=+17

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