39(2y+1)=6y+3

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Solution for 39(2y+1)=6y+3 equation: 



39(2y+1)=6y+3

We move all terms to the left:

39(2y+1)-(6y+3)=0

We multiply parentheses

78y-(6y+3)+39=0

We get rid of parentheses

78y-6y-3+39=0

We add all the numbers together, and all the variables

72y+36=0

We move all terms containing y to the left, all other terms to the right

72y=-36

y=-36/72

y=-1/2

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