-6(w+2)=5w-2+2(2w+1)

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Solution for -6(w+2)=5w-2+2(2w+1) equation: 



-6(w+2)=5w-2+2(2w+1)

We move all terms to the left:

-6(w+2)-(5w-2+2(2w+1))=0

We multiply parentheses

-6w-(5w-2+2(2w+1))-12=0



We calculate terms in parentheses: -(5w-2+2(2w+1)), so:

5w-2+2(2w+1)

determiningTheFunctionDomain
5w+2(2w+1)-2

We multiply parentheses

5w+4w+2-2

We add all the numbers together, and all the variables

9w

Back to the equation:

-(9w)



We add all the numbers together, and all the variables

-15w-12=0

We move all terms containing w to the left, all other terms to the right

-15w=12

w=12/-15

w=-4/5

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