6(n+4)+5(2-2n)=30

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Solution for 6(n+4)+5(2-2n)=30 equation: 



6(n+4)+5(2-2n)=30

We move all terms to the left:

6(n+4)+5(2-2n)-(30)=0

We add all the numbers together, and all the variables

6(n+4)+5(-2n+2)-30=0

We multiply parentheses

6n-10n+24+10-30=0

We add all the numbers together, and all the variables

-4n+4=0

We move all terms containing n to the left, all other terms to the right

-4n=-4

n=-4/-4

n=1

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