2(c-4)-5(2c+1)=4(2c+6)-1

Solution for 2(c-4)-5(2c+1)=4(2c+6)-1 equation:

2(c-4)-5(2c+1)=4(2c+6)-1

We move all terms to the left:

2(c-4)-5(2c+1)-(4(2c+6)-1)=0

We multiply parentheses

2c-10c-(4(2c+6)-1)-8-5=0


We calculate terms in parentheses: -(4(2c+6)-1), so:

4(2c+6)-1

We multiply parentheses

8c+24-1

We add all the numbers together, and all the variables

8c+23

Back to the equation:

-(8c+23)


We add all the numbers together, and all the variables

-8c-(8c+23)-13=0

We get rid of parentheses

-8c-8c-23-13=0

We add all the numbers together, and all the variables

-16c-36=0

We move all terms containing c to the left, all other terms to the right

-16c=36

c=36/-16

c=-2+1/4