-6(u+1)=4u-8+2(3u+8)

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Solution for -6(u+1)=4u-8+2(3u+8) equation: 



-6(u+1)=4u-8+2(3u+8)

We move all terms to the left:

-6(u+1)-(4u-8+2(3u+8))=0

We multiply parentheses

-6u-(4u-8+2(3u+8))-6=0



We calculate terms in parentheses: -(4u-8+2(3u+8)), so:

4u-8+2(3u+8)

determiningTheFunctionDomain
4u+2(3u+8)-8

We multiply parentheses

4u+6u+16-8

We add all the numbers together, and all the variables

10u+8

Back to the equation:

-(10u+8)



We get rid of parentheses

-6u-10u-8-6=0

We add all the numbers together, and all the variables

-16u-14=0

We move all terms containing u to the left, all other terms to the right

-16u=14

u=14/-16

u=-7/8

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