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(1/3)*a+2=2a+1
We move all terms to the left:
(1/3)*a+2-(2a+1)=0
Domain of the equation: 3)*a!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
(+1/3)*a-(2a+1)+2=0
We multiply parentheses
a^2-(2a+1)+2=0
We get rid of parentheses
a^2-2a-1+2=0
We add all the numbers together, and all the variables
a^2-2a+1=0
a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{2}{2}=1$
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