7(x-3)=2x-41

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Solution for 7(x-3)=2x-41 equation: 



7(x-3)=2x-41

We move all terms to the left:

7(x-3)-(2x-41)=0

We multiply parentheses

7x-(2x-41)-21=0

We get rid of parentheses

7x-2x+41-21=0

We add all the numbers together, and all the variables

5x+20=0

We move all terms containing x to the left, all other terms to the right

5x=-20

x=-20/5

x=-4

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