4x+10=-12+3(x-2)

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Solution for 4x+10=-12+3(x-2) equation: 



4x+10=-12+3(x-2)

We move all terms to the left:

4x+10-(-12+3(x-2))=0



We calculate terms in parentheses: -(-12+3(x-2)), so:

-12+3(x-2)

determiningTheFunctionDomain
3(x-2)-12

We multiply parentheses

3x-6-12

We add all the numbers together, and all the variables

3x-18

Back to the equation:

-(3x-18)



We get rid of parentheses

4x-3x+18+10=0

We add all the numbers together, and all the variables

x+28=0

We move all terms containing x to the left, all other terms to the right

x=-28

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