2(x+2)+2(3x-1)=66

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Solution for 2(x+2)+2(3x-1)=66 equation: 



2(x+2)+2(3x-1)=66

We move all terms to the left:

2(x+2)+2(3x-1)-(66)=0

We multiply parentheses

2x+6x+4-2-66=0

We add all the numbers together, and all the variables

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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