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112=2(6v+2)
We move all terms to the left:
112-(2(6v+2))=0
We calculate terms in parentheses: -(2(6v+2)), so:We get rid of parentheses
2(6v+2)
We multiply parentheses
12v+4
Back to the equation:
-(12v+4)
-12v-4+112=0
We add all the numbers together, and all the variables
-12v+108=0
We move all terms containing v to the left, all other terms to the right
-12v=-108
v=-108/-12
v=+9
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