-6(2w-2)+w=5(w+3)

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Solution for -6(2w-2)+w=5(w+3) equation: 



-6(2w-2)+w=5(w+3)

We move all terms to the left:

-6(2w-2)+w-(5(w+3))=0

We add all the numbers together, and all the variables

w-6(2w-2)-(5(w+3))=0

We multiply parentheses

w-12w-(5(w+3))+12=0



We calculate terms in parentheses: -(5(w+3)), so:

5(w+3)

We multiply parentheses

5w+15

Back to the equation:

-(5w+15)



We add all the numbers together, and all the variables

-11w-(5w+15)+12=0

We get rid of parentheses

-11w-5w-15+12=0

We add all the numbers together, and all the variables

-16w-3=0

We move all terms containing w to the left, all other terms to the right

-16w=3

w=3/-16

w=-3/16

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