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4.9x^2+19.5x+-59.4=0
We add all the numbers together, and all the variables
4.9x^2+19.5x=0
a = 4.9; b = 19.5; c = 0;
Δ = b2-4ac
Δ = 19.52-4·4.9·0
Δ = 380.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19.5)-\sqrt{380.25}}{2*4.9}=\frac{-19.5-\sqrt{380.25}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19.5)+\sqrt{380.25}}{2*4.9}=\frac{-19.5+\sqrt{380.25}}{9.8} $
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