4y+2-2(-3y-1)=2(y-4)

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Solution for 4y+2-2(-3y-1)=2(y-4) equation: 



4y+2-2(-3y-1)=2(y-4)

We move all terms to the left:

4y+2-2(-3y-1)-(2(y-4))=0

We multiply parentheses

4y+6y-(2(y-4))+2+2=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We add all the numbers together, and all the variables

10y-(2y-8)+4=0

We get rid of parentheses

10y-2y+8+4=0

We add all the numbers together, and all the variables

8y+12=0

We move all terms containing y to the left, all other terms to the right

8y=-12

y=-12/8

y=-1+1/2

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