-6(10-j)+2=2(3j)-58

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Solution for -6(10-j)+2=2(3j)-58 equation: 



-6(10-j)+2=2(3j)-58

We move all terms to the left:

-6(10-j)+2-(2(3j)-58)=0

We add all the numbers together, and all the variables

-6(-1j+10)-(23j-58)+2=0

We multiply parentheses

6j-(23j-58)-60+2=0

We get rid of parentheses

6j-23j+58-60+2=0

We add all the numbers together, and all the variables

-17j=0

j=0/-17

j=0

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