2(x-8)=8(x+3)+8

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Solution for 2(x-8)=8(x+3)+8 equation: 



2(x-8)=8(x+3)+8

We move all terms to the left:

2(x-8)-(8(x+3)+8)=0

We multiply parentheses

2x-(8(x+3)+8)-16=0



We calculate terms in parentheses: -(8(x+3)+8), so:

8(x+3)+8

We multiply parentheses

8x+24+8

We add all the numbers together, and all the variables

8x+32

Back to the equation:

-(8x+32)



We get rid of parentheses

2x-8x-32-16=0

We add all the numbers together, and all the variables

-6x-48=0

We move all terms containing x to the left, all other terms to the right

-6x=48

x=48/-6

x=-8

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