3z-4(z+1)=8z+3

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Solution for 3z-4(z+1)=8z+3 equation: 



3z-4(z+1)=8z+3

We move all terms to the left:

3z-4(z+1)-(8z+3)=0

We multiply parentheses

3z-4z-(8z+3)-4=0

We get rid of parentheses

3z-4z-8z-3-4=0

We add all the numbers together, and all the variables

-9z-7=0

We move all terms containing z to the left, all other terms to the right

-9z=7

z=7/-9

z=-7/9

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