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-5/8x+4=3/2x
We move all terms to the left:
-5/8x+4-(3/2x)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-5/8x-(+3/2x)+4=0
We get rid of parentheses
-5/8x-3/2x+4=0
We calculate fractions
(-10x)/16x^2+(-24x)/16x^2+4=0
We multiply all the terms by the denominator
(-10x)+(-24x)+4*16x^2=0
Wy multiply elements
64x^2+(-10x)+(-24x)=0
We get rid of parentheses
64x^2-10x-24x=0
We add all the numbers together, and all the variables
64x^2-34x=0
a = 64; b = -34; c = 0;
Δ = b2-4ac
Δ = -342-4·64·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-34}{2*64}=\frac{0}{128} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+34}{2*64}=\frac{68}{128} =17/32 $
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