17-(4k-2)=2(k-4)

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Solution for 17-(4k-2)=2(k-4) equation: 



17-(4k-2)=2(k-4)

We move all terms to the left:

17-(4k-2)-(2(k-4))=0

We get rid of parentheses

-4k-(2(k-4))+2+17=0



We calculate terms in parentheses: -(2(k-4)), so:

2(k-4)

We multiply parentheses

2k-8

Back to the equation:

-(2k-8)



We add all the numbers together, and all the variables

-4k-(2k-8)+19=0

We get rid of parentheses

-4k-2k+8+19=0

We add all the numbers together, and all the variables

-6k+27=0

We move all terms containing k to the left, all other terms to the right

-6k=-27

k=-27/-6

k=4+1/2

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