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(x+80)(6x)=180
We move all terms to the left:
(x+80)(6x)-(180)=0
We multiply parentheses
6x^2+480x-180=0
a = 6; b = 480; c = -180;
Δ = b2-4ac
Δ = 4802-4·6·(-180)
Δ = 234720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{234720}=\sqrt{144*1630}=\sqrt{144}*\sqrt{1630}=12\sqrt{1630}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(480)-12\sqrt{1630}}{2*6}=\frac{-480-12\sqrt{1630}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(480)+12\sqrt{1630}}{2*6}=\frac{-480+12\sqrt{1630}}{12} $
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