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-5/6x-4=1/2x
We move all terms to the left:
-5/6x-4-(1/2x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-5/6x-(+1/2x)-4=0
We get rid of parentheses
-5/6x-1/2x-4=0
We calculate fractions
(-10x)/12x^2+(-6x)/12x^2-4=0
We multiply all the terms by the denominator
(-10x)+(-6x)-4*12x^2=0
Wy multiply elements
-48x^2+(-10x)+(-6x)=0
We get rid of parentheses
-48x^2-10x-6x=0
We add all the numbers together, and all the variables
-48x^2-16x=0
a = -48; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-48)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-48}=\frac{0}{-96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-48}=\frac{32}{-96} =-1/3 $
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