6x-2(x+3)=4(x-3)+6

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Solution for 6x-2(x+3)=4(x-3)+6 equation: 



6x-2(x+3)=4(x-3)+6

We move all terms to the left:

6x-2(x+3)-(4(x-3)+6)=0

We multiply parentheses

6x-2x-(4(x-3)+6)-6=0



We calculate terms in parentheses: -(4(x-3)+6), so:

4(x-3)+6

We multiply parentheses

4x-12+6

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

4x-(4x-6)-6=0

We get rid of parentheses

4x-4x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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