2(3x-5)+x+4=-3(x+1)

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Solution for 2(3x-5)+x+4=-3(x+1) equation: 



2(3x-5)+x+4=-3(x+1)

We move all terms to the left:

2(3x-5)+x+4-(-3(x+1))=0

We add all the numbers together, and all the variables

x+2(3x-5)-(-3(x+1))+4=0

We multiply parentheses

x+6x-(-3(x+1))-10+4=0



We calculate terms in parentheses: -(-3(x+1)), so:

-3(x+1)

We multiply parentheses

-3x-3

Back to the equation:

-(-3x-3)



We add all the numbers together, and all the variables

7x-(-3x-3)-6=0

We get rid of parentheses

7x+3x+3-6=0

We add all the numbers together, and all the variables

10x-3=0

We move all terms containing x to the left, all other terms to the right

10x=3

x=3/10

x=3/10

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