-5(y-7)=30-(2y+1)

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Solution for -5(y-7)=30-(2y+1) equation: 



-5(y-7)=30-(2y+1)

We move all terms to the left:

-5(y-7)-(30-(2y+1))=0

We multiply parentheses

-5y-(30-(2y+1))+35=0



We calculate terms in parentheses: -(30-(2y+1)), so:

30-(2y+1)

determiningTheFunctionDomain
-(2y+1)+30

We get rid of parentheses

-2y-1+30

We add all the numbers together, and all the variables

-2y+29

Back to the equation:

-(-2y+29)



We get rid of parentheses

-5y+2y-29+35=0

We add all the numbers together, and all the variables

-3y+6=0

We move all terms containing y to the left, all other terms to the right

-3y=-6

y=-6/-3

y=+2

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