-2(v+2)=4v-5+3(4v+5)

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Solution for -2(v+2)=4v-5+3(4v+5) equation: 



-2(v+2)=4v-5+3(4v+5)

We move all terms to the left:

-2(v+2)-(4v-5+3(4v+5))=0

We multiply parentheses

-2v-(4v-5+3(4v+5))-4=0



We calculate terms in parentheses: -(4v-5+3(4v+5)), so:

4v-5+3(4v+5)

determiningTheFunctionDomain
4v+3(4v+5)-5

We multiply parentheses

4v+12v+15-5

We add all the numbers together, and all the variables

16v+10

Back to the equation:

-(16v+10)



We get rid of parentheses

-2v-16v-10-4=0

We add all the numbers together, and all the variables

-18v-14=0

We move all terms containing v to the left, all other terms to the right

-18v=14

v=14/-18

v=-7/9

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