-5(x+3)+147=32+10

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Solution for -5(x+3)+147=32+10 equation: 



-5(x+3)+147=32+10

We move all terms to the left:

-5(x+3)+147-(32+10)=0

We add all the numbers together, and all the variables

-5(x+3)+147-42=0

We add all the numbers together, and all the variables

-5(x+3)+105=0

We multiply parentheses

-5x-15+105=0

We add all the numbers together, and all the variables

-5x+90=0

We move all terms containing x to the left, all other terms to the right

-5x=-90

x=-90/-5

x=+18

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