2(3/2y-19)-3=-19

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Solution for 2(3/2y-19)-3=-19 equation: 



2(3/2y-19)-3=-19

We move all terms to the left:

2(3/2y-19)-3-(-19)=0



Domain of the equation: 2y-19)!=0

y∈R



We add all the numbers together, and all the variables

2(3/2y-19)+16=0

We multiply parentheses

6y-38+16=0

We add all the numbers together, and all the variables

6y-22=0

We move all terms containing y to the left, all other terms to the right

6y=22

y=22/6

y=3+2/3

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