3+2-19k=6(-14k-12)+12

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Solution for 3+2-19k=6(-14k-12)+12 equation: 



3+2-19k=6(-14k-12)+12

We move all terms to the left:

3+2-19k-(6(-14k-12)+12)=0

We add all the numbers together, and all the variables

-19k-(6(-14k-12)+12)+5=0



We calculate terms in parentheses: -(6(-14k-12)+12), so:

6(-14k-12)+12

We multiply parentheses

-84k-72+12

We add all the numbers together, and all the variables

-84k-60

Back to the equation:

-(-84k-60)



We get rid of parentheses

-19k+84k+60+5=0

We add all the numbers together, and all the variables

65k+65=0

We move all terms containing k to the left, all other terms to the right

65k=-65

k=-65/65

k=-1

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