-5(4n-5)=-29-2n

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Solution for -5(4n-5)=-29-2n equation: 



-5(4n-5)=-29-2n

We move all terms to the left:

-5(4n-5)-(-29-2n)=0

We add all the numbers together, and all the variables

-5(4n-5)-(-2n-29)=0

We multiply parentheses

-20n-(-2n-29)+25=0

We get rid of parentheses

-20n+2n+29+25=0

We add all the numbers together, and all the variables

-18n+54=0

We move all terms containing n to the left, all other terms to the right

-18n=-54

n=-54/-18

n=+3

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