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15+(2x-3)=10x-(x3-2)
We move all terms to the left:
15+(2x-3)-(10x-(x3-2))=0
We add all the numbers together, and all the variables
-(10x-(+x^3-2))+(2x-3)+15=0
We get rid of parentheses
-(10x-(+x^3-2))+2x-3+15=0
We calculate terms in parentheses: -(10x-(+x^3-2)), so:
10x-(+x^3-2)
We do not support expression: x^3
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