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3x-2(x+5)=7(x+1)-6x
We move all terms to the left:
3x-2(x+5)-(7(x+1)-6x)=0
We multiply parentheses
3x-2x-(7(x+1)-6x)-10=0
We calculate terms in parentheses: -(7(x+1)-6x), so:We add all the numbers together, and all the variables
7(x+1)-6x
We add all the numbers together, and all the variables
-6x+7(x+1)
We multiply parentheses
-6x+7x+7
We add all the numbers together, and all the variables
x+7
Back to the equation:
-(x+7)
x-(x+7)-10=0
We get rid of parentheses
x-x-7-10=0
We add all the numbers together, and all the variables
-17!=0
There is no solution for this equation
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