-5(2y-5)-y=-2(y-4)

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Solution for -5(2y-5)-y=-2(y-4) equation: 



-5(2y-5)-y=-2(y-4)

We move all terms to the left:

-5(2y-5)-y-(-2(y-4))=0

We add all the numbers together, and all the variables

-1y-5(2y-5)-(-2(y-4))=0

We multiply parentheses

-1y-10y-(-2(y-4))+25=0



We calculate terms in parentheses: -(-2(y-4)), so:

-2(y-4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We add all the numbers together, and all the variables

-11y-(-2y+8)+25=0

We get rid of parentheses

-11y+2y-8+25=0

We add all the numbers together, and all the variables

-9y+17=0

We move all terms containing y to the left, all other terms to the right

-9y=-17

y=-17/-9

y=1+8/9

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