56-(3c+4)=4(c+5)=c

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Solution for 56-(3c+4)=4(c+5)=c equation: 



56-(3c+4)=4(c+5)=c

We move all terms to the left:

56-(3c+4)-(4(c+5))=0

We get rid of parentheses

-3c-(4(c+5))-4+56=0



We calculate terms in parentheses: -(4(c+5)), so:

4(c+5)

We multiply parentheses

4c+20

Back to the equation:

-(4c+20)



We add all the numbers together, and all the variables

-3c-(4c+20)+52=0

We get rid of parentheses

-3c-4c-20+52=0

We add all the numbers together, and all the variables

-7c+32=0

We move all terms containing c to the left, all other terms to the right

-7c=-32

c=-32/-7

c=4+4/7

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