2/3(9-6s)=4(s+3)

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Solution for 2/3(9-6s)=4(s+3) equation: 



2/3(9-6s)=4(s+3)

We move all terms to the left:

2/3(9-6s)-(4(s+3))=0



Domain of the equation: 3(9-6s)!=0

s∈R



We add all the numbers together, and all the variables

2/3(-6s+9)-(4(s+3))=0

We multiply all the terms by the denominator


-((4(s+3)))*3(-6s+9)+2=0



We calculate terms in parentheses: -((4(s+3)))*3(-6s+9), so:

(4(s+3)))*3(-6s+9

We add all the numbers together, and all the variables

-6s+(4(s+3)))*3(+9

Back to the equation:

-(-6s+(4(s+3)))*3(+9)



We add all the numbers together, and all the variables

-(-6s+(4(s+3)))*39+2=0

We move all terms containing s to the left, all other terms to the right

-(-6s+(4(s+3)))*39=-2

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