-5(2v-1)+4v=5+2(4v-1)

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Solution for -5(2v-1)+4v=5+2(4v-1) equation: 



-5(2v-1)+4v=5+2(4v-1)

We move all terms to the left:

-5(2v-1)+4v-(5+2(4v-1))=0

We add all the numbers together, and all the variables

4v-5(2v-1)-(5+2(4v-1))=0

We multiply parentheses

4v-10v-(5+2(4v-1))+5=0



We calculate terms in parentheses: -(5+2(4v-1)), so:

5+2(4v-1)

determiningTheFunctionDomain
2(4v-1)+5

We multiply parentheses

8v-2+5

We add all the numbers together, and all the variables

8v+3

Back to the equation:

-(8v+3)



We add all the numbers together, and all the variables

-6v-(8v+3)+5=0

We get rid of parentheses

-6v-8v-3+5=0

We add all the numbers together, and all the variables

-14v+2=0

We move all terms containing v to the left, all other terms to the right

-14v=-2

v=-2/-14

v=1/7

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