-5(3y-4)+8y=3(y+6)

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Solution for -5(3y-4)+8y=3(y+6) equation: 



-5(3y-4)+8y=3(y+6)

We move all terms to the left:

-5(3y-4)+8y-(3(y+6))=0

We add all the numbers together, and all the variables

8y-5(3y-4)-(3(y+6))=0

We multiply parentheses

8y-15y-(3(y+6))+20=0



We calculate terms in parentheses: -(3(y+6)), so:

3(y+6)

We multiply parentheses

3y+18

Back to the equation:

-(3y+18)



We add all the numbers together, and all the variables

-7y-(3y+18)+20=0

We get rid of parentheses

-7y-3y-18+20=0

We add all the numbers together, and all the variables

-10y+2=0

We move all terms containing y to the left, all other terms to the right

-10y=-2

y=-2/-10

y=1/5

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