13r-4(r+2)=3(4r-6)-2

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Solution for 13r-4(r+2)=3(4r-6)-2 equation: 



13r-4(r+2)=3(4r-6)-2

We move all terms to the left:

13r-4(r+2)-(3(4r-6)-2)=0

We multiply parentheses

13r-4r-(3(4r-6)-2)-8=0



We calculate terms in parentheses: -(3(4r-6)-2), so:

3(4r-6)-2

We multiply parentheses

12r-18-2

We add all the numbers together, and all the variables

12r-20

Back to the equation:

-(12r-20)



We add all the numbers together, and all the variables

9r-(12r-20)-8=0

We get rid of parentheses

9r-12r+20-8=0

We add all the numbers together, and all the variables

-3r+12=0

We move all terms containing r to the left, all other terms to the right

-3r=-12

r=-12/-3

r=+4

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