-5(1-b)-6b=-2(b+2)

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Solution for -5(1-b)-6b=-2(b+2) equation: 



-5(1-b)-6b=-2(b+2)

We move all terms to the left:

-5(1-b)-6b-(-2(b+2))=0

We add all the numbers together, and all the variables

-5(-1b+1)-6b-(-2(b+2))=0

We add all the numbers together, and all the variables

-6b-5(-1b+1)-(-2(b+2))=0

We multiply parentheses

-6b+5b-(-2(b+2))-5=0



We calculate terms in parentheses: -(-2(b+2)), so:

-2(b+2)

We multiply parentheses

-2b-4

Back to the equation:

-(-2b-4)



We add all the numbers together, and all the variables

-1b-(-2b-4)-5=0

We get rid of parentheses

-1b+2b+4-5=0

We add all the numbers together, and all the variables

b-1=0

We move all terms containing b to the left, all other terms to the right

b=1

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