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x(x+43)=90
We move all terms to the left:
x(x+43)-(90)=0
We multiply parentheses
x^2+43x-90=0
a = 1; b = 43; c = -90;
Δ = b2-4ac
Δ = 432-4·1·(-90)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-47}{2*1}=\frac{-90}{2} =-45 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+47}{2*1}=\frac{4}{2} =2 $
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