35-7z=5(z-5)

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Solution for 35-7z=5(z-5) equation: 



35-7z=5(z-5)

We move all terms to the left:

35-7z-(5(z-5))=0



We calculate terms in parentheses: -(5(z-5)), so:

5(z-5)

We multiply parentheses

5z-25

Back to the equation:

-(5z-25)



We get rid of parentheses

-7z-5z+25+35=0

We add all the numbers together, and all the variables

-12z+60=0

We move all terms containing z to the left, all other terms to the right

-12z=-60

z=-60/-12

z=+5

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