-5(-2y+3)=3y+2(3y-5)

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Solution for -5(-2y+3)=3y+2(3y-5) equation: 



-5(-2y+3)=3y+2(3y-5)

We move all terms to the left:

-5(-2y+3)-(3y+2(3y-5))=0

We multiply parentheses

10y-(3y+2(3y-5))-15=0



We calculate terms in parentheses: -(3y+2(3y-5)), so:

3y+2(3y-5)

We multiply parentheses

3y+6y-10

We add all the numbers together, and all the variables

9y-10

Back to the equation:

-(9y-10)



We get rid of parentheses

10y-9y+10-15=0

We add all the numbers together, and all the variables

y-5=0

We move all terms containing y to the left, all other terms to the right

y=5

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